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| 07.18.2008 at 08:27PM PDT, ID: 23578683 |
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Attachment Details
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The Solution Rating System
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With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.
Your Input Matters If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support. Thank you! |
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SELECT C.DisplayName AS 'Contact', F.FirmName, F.Address, F.City,
S.StateName, F.PostCode, (SELECT @JobDateFrom + ' ~ ' + @JobDateTo) AS JobDates, B.BUID,
COUNT(DISTINCT J.JobNo) AS 'Jobs'
FROM Jobs J JOIN JobsParties JP ON J.JobNo = JP.JobNo
LEFT OUTER JOIN JobsPartiesSvc JPS ON JP.JobPartyNo = JPS.JobPartyNo
LEFT OUTER JOIN Contacts C ON J.OrdContactNo = C.ContactNo
LEFT OUTER JOIN Firms F ON C.FirmNo = F.FirmNo
LEFT OUTER JOIN State S ON F.StateNo = S.StateNo
LEFT OUTER JOIN Invoices I ON J.JobNo = I.JobNo
LEFT OUTER JOIN BU B ON B.BUNo = J.BUNo
WHERE J.Status NOT IN (712,812,811)
AND J.JobDate BETWEEN @JobDateFrom and @JobDateTo
GROUP BY C.DisplayName, F.FirmName, F.Address, F.City, F.PostCode, S.StateName, B.BUID
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